Work, Energy, Power and Simple Machines
Physics · WAEC and JAMB · SS2 and SS3
This topic rewards candidates who keep their units straight, since work is in joules, power in watts and efficiency has no unit at all. WAEC commonly pairs an energy-conversion calculation with a machine question on mechanical advantage, velocity ratio and efficiency.
What you need to know
- Work is done when a force moves its point of application through a distance in the direction of the force: W = F d cos theta, where theta is the angle between the force and the displacement. A man carrying a load on his head along a level road does no work against gravity, because the force is vertical and the motion horizontal.
- Energy is the capacity to do work, and both are measured in joules. One joule is the work done when a force of one newton moves a body through one metre in the direction of the force.
- Kinetic energy is the energy a body has by virtue of its motion, KE = (1/2)mv^2. Potential energy due to position is PE = mgh; elastic potential energy stored in a stretched spring is (1/2)ke^2.
- The principle of conservation of energy states that energy can neither be created nor destroyed but only converted from one form to another. For a body falling freely, the loss in potential energy equals the gain in kinetic energy, so mgh = (1/2)mv^2 and v = sqrt(2gh).
- Power is the rate of doing work or the rate of transfer of energy, P = W/t, measured in watts. For a body moving at steady velocity against a resisting force, P = F v.
- Energy forms you must be able to name and convert between: mechanical, heat, light, sound, electrical, chemical, nuclear and solar. A torch converts chemical to electrical to light and heat; a generator converts chemical to mechanical to electrical.
- A machine is any device that allows a force applied at one point (the effort) to overcome a force at another point (the load). Machines do not create energy; they trade force against distance.
- Mechanical advantage MA = load / effort, velocity ratio VR = distance moved by effort / distance moved by load, and efficiency = (MA/VR) x 100 per cent, which is also (work output / work input) x 100.
- No practical machine is 100 per cent efficient, because some work input is always spent overcoming friction between moving parts and lifting the movable parts of the machine itself. Efficiency improves with lubrication and lighter moving parts.
- For a lever, the principle of moments gives load x load arm = effort x effort arm, so MA = VR for an ideal lever. First-class levers have the fulcrum between load and effort (scissors, seesaw, pliers); second-class have the load between (wheelbarrow, nutcracker); third-class have the effort between (forceps, the human forearm, a fishing rod).
- For a block and tackle pulley system, the velocity ratio equals the number of pulleys, or more precisely the number of rope sections supporting the movable block. A single fixed pulley has VR = 1 and merely changes the direction of the effort.
- For an inclined plane, VR = length of plane / vertical height = 1/sin(theta). For a screw jack, VR = 2 pi R / pitch, where R is the length of the handle. For a wheel and axle, VR = radius of wheel / radius of axle.
- In a hydraulic press, the velocity ratio is the ratio of the areas, A(large)/A(small), and the pressure is transmitted equally throughout the liquid, which is Pascal's principle used as a force multiplier.
- A moment of a force about a point is force times perpendicular distance from the point, measured in N m. A body in equilibrium obeys both conditions: the sum of the forces is zero and the sum of clockwise moments about any point equals the sum of anticlockwise moments.
Key terms
- Work
- The product of a force and the distance moved by its point of application in the direction of the force.
- Energy
- The capacity of a body to do work, measured in joules.
- Power
- The rate at which work is done or energy is transferred, measured in watts.
- Mechanical advantage
- The ratio of the load overcome by a machine to the effort applied to it.
- Velocity ratio
- The ratio of the distance moved by the effort to the distance moved by the load in the same time.
- Efficiency
- The ratio of the useful work output of a machine to the work input, expressed as a percentage.
- Moment of a force
- The product of the force and the perpendicular distance of its line of action from the pivot.
Formulae
W = F*d*cos(theta)KE = (1/2)*m*v^2PE = m*g*helastic PE = (1/2)*k*e^2v = sqrt(2*g*h) for a body falling from rest through hP = W/t and P = F*vMA = load / effortVR = distance moved by effort / distance moved by loadefficiency = (MA / VR) * 100 = (work output / work input) * 100lever: load * load arm = effort * effort arminclined plane: VR = 1/sin(theta)screw jack: VR = 2*pi*R / pitchhydraulic press: VR = A(large)/A(small)
Worked examples
A pump raises 600 kg of water through a vertical height of 10 m in 20 s. Taking g = 10 m/s^2, calculate the useful power output of the pump. If the pump is 75 per cent efficient, what input power does it require?
- Useful work done against gravity = m g h = 600 x 10 x 10 = 60 000 J.
- Useful power output = work / time = 60 000 / 20 = 3000 W = 3.0 kW.
- Efficiency = (output power / input power) x 100, so 75 = (3000 / input) x 100.
- Input power = 3000 x 100 / 75 = 4000 W = 4.0 kW.
- Check: 75 per cent of 4000 W is 3000 W, which matches the useful output.
Answer: Useful power output = 3000 W (3.0 kW); input power required = 4000 W (4.0 kW)
A block and tackle system of 4 pulleys is used to raise a load of 800 N using an effort of 250 N. Calculate the mechanical advantage, the velocity ratio and the efficiency of the machine.
- Mechanical advantage MA = load / effort = 800 / 250 = 3.2.
- Velocity ratio for a block and tackle equals the number of pulleys, so VR = 4.
- Efficiency = (MA / VR) x 100 = (3.2 / 4) x 100 = 80 per cent.
- Cross-check with work: if the load rises 2 m, the effort moves 4 x 2 = 8 m. Work output = 800 x 2 = 1600 J and work input = 250 x 8 = 2000 J.
- Efficiency = (1600 / 2000) x 100 = 80 per cent, which agrees.
Answer: MA = 3.2; VR = 4; efficiency = 80 per cent
The mistake to avoid
Candidates write efficiency as a value greater than 100 per cent because they invert the fraction, dividing VR by MA or work input by work output. Efficiency can never exceed 100 per cent; if your answer does, you have flipped the ratio. Many also attach a unit to efficiency, MA or VR, but all three are pure ratios with no unit.
In the exam
Machine questions nearly always give you load, effort and either the number of pulleys or a distance ratio, so identify MA and VR separately before touching efficiency. In energy questions state the conversion in words first, for example chemical to electrical to light, since the examiner marks the chain. Keep power in watts unless the question asks for kilowatts, and never confuse the kilowatt with the kilowatt-hour.