Heat: Expansion, Capacity, Gas Laws, Transfer
Physics · WAEC and JAMB · SS2 and SS3
Heat questions carry easy marks because the formulae are few and the arithmetic is direct, yet candidates lose them on temperature conversion and on latent heat. Expect a mixtures or latent heat calculation and a gas law calculation almost every year.
What you need to know
- Heat is a form of energy measured in joules; temperature is the degree of hotness of a body and determines the direction of heat flow. Heat always flows from a body at higher temperature to one at lower temperature until they reach thermal equilibrium.
- Celsius and kelvin are related by T(K) = theta(C) + 273. Absolute zero is 0 K or -273 degrees Celsius. Fahrenheit converts by F = (9/5)C + 32, and the two scales read the same at -40 degrees.
- Thermometers use any property that varies regularly with temperature: the liquid-in-glass thermometer uses expansion of mercury or alcohol, the resistance thermometer uses electrical resistance of platinum, the thermocouple uses the emf between two different metals, and the constant-volume gas thermometer uses gas pressure.
- Mercury is chosen for thermometers because it is opaque and easily seen, expands uniformly, is a good conductor, does not wet glass, and has a wide range from -39 to 357 degrees Celsius. Alcohol is preferred in very cold regions because it freezes at about -112 degrees Celsius, well below the freezing point of mercury.
- Linear expansivity (alpha) is the fractional increase in length per degree rise in temperature. Area expansivity is 2 alpha and volume (cubic) expansivity is 3 alpha for the same solid.
- Expansion must be allowed for in engineering: gaps are left between rails and between bridge sections, telephone and transmission wires are hung slack, and a bimetallic strip of brass and iron bends on heating because brass expands more, which is how fire alarms and thermostats work.
- Water shows anomalous expansion between 0 and 4 degrees Celsius: it contracts as it is heated from 0 to 4 degrees and expands above 4. Water therefore has its maximum density at 4 degrees, which is why ice floats and why fish survive under a frozen pond surface.
- Heat capacity C is the heat needed to raise the temperature of a whole body by one kelvin, in J/K. Specific heat capacity c is the heat needed to raise unit mass by one kelvin, in J/kg/K, and Q = m c (theta2 - theta1). Water has an unusually high specific heat capacity of 4200 J/kg/K, which is why it is used as a coolant in car radiators.
- Latent heat is the heat absorbed or given out during a change of state at constant temperature. Specific latent heat of fusion is the heat needed to change unit mass of solid to liquid at its melting point; specific latent heat of vaporisation does the same from liquid to vapour. Use Q = m l, with no temperature term.
- In the method of mixtures, heat lost by the hot body equals heat gained by the cold body and the calorimeter, assuming no heat is lost to the surroundings. This single statement is the backbone of every calorimetry calculation.
- Boyle's law: at constant temperature, PV = constant, so P1V1 = P2V2. Charles's law: at constant pressure, V/T = constant, with T in kelvin. Pressure law: at constant volume, P/T = constant. Combining them gives the general gas equation P1V1/T1 = P2V2/T2.
- Evaporation occurs at all temperatures and only at the surface of the liquid, while boiling occurs throughout the liquid at one fixed temperature. Evaporation is increased by a larger surface area, higher temperature, moving dry air and lower pressure, and it causes cooling because the fastest molecules escape.
- Heat travels by conduction through solids as particles vibrate and pass energy on, by convection in fluids as warm, less dense regions rise and cooler regions sink, and by radiation as electromagnetic waves needing no material medium, which is how the sun reaches the earth.
- A vacuum flask blocks all three: the vacuum between the double walls stops conduction and convection, the silvered surfaces reflect radiation, and the cork or plastic stopper stops convection currents and conduction through the top. Dull black surfaces are the best absorbers and emitters of radiation; bright shiny surfaces are the worst.
Key terms
- Heat capacity
- The quantity of heat required to raise the temperature of a given body by one kelvin.
- Specific heat capacity
- The quantity of heat required to raise the temperature of one kilogram of a substance by one kelvin.
- Specific latent heat of fusion
- The heat required to change one kilogram of a solid to liquid at its melting point without any change in temperature.
- Specific latent heat of vaporisation
- The heat required to change one kilogram of a liquid to vapour at its boiling point without any change in temperature.
- Linear expansivity
- The increase in length per unit length per degree rise in temperature.
- Boyle's law
- The volume of a fixed mass of gas is inversely proportional to its pressure, provided the temperature remains constant.
- Convection
- The transfer of heat through a fluid by the actual movement of the heated fluid itself.
Formulae
T(K) = theta(C) + 273Q = m*c*(theta2 - theta1)Q = m*l for a change of stateheat capacity C = m*c, so Q = C*(theta2 - theta1)heat lost by hot body = heat gained by cold bodylinear expansion: l2 = l1*(1 + alpha*(theta2 - theta1))alpha = (l2 - l1) / (l1 * temperature rise)area expansivity = 2*alpha, cubic expansivity = 3*alphaBoyle: P1*V1 = P2*V2Charles: V1/T1 = V2/T2Pressure law: P1/T1 = P2/T2general gas equation: P1*V1/T1 = P2*V2/T2
Worked examples
Calculate the quantity of heat required to convert 200 g of ice at 0 degrees Celsius completely into water at 40 degrees Celsius. Take the specific latent heat of fusion of ice as 3.3 x 10^5 J/kg and the specific heat capacity of water as 4200 J/kg/K.
- Convert the mass: 200 g = 0.200 kg.
- Stage 1, melting the ice at 0 degrees Celsius with no temperature change: Q1 = m l = 0.200 x 3.3 x 10^5 = 66 000 J.
- Stage 2, heating the resulting water from 0 to 40 degrees Celsius: Q2 = m c (theta2 - theta1) = 0.200 x 4200 x 40.
- Q2 = 0.200 x 4200 = 840; 840 x 40 = 33 600 J.
- Total heat required Q = Q1 + Q2 = 66 000 + 33 600 = 99 600 J.
Answer: 99 600 J, that is approximately 9.96 x 10^4 J
A fixed mass of gas occupies 250 cm^3 at 27 degrees Celsius and 760 mmHg. Calculate its volume at 87 degrees Celsius and 1140 mmHg.
- Convert both temperatures to kelvin: T1 = 27 + 273 = 300 K and T2 = 87 + 273 = 360 K.
- Use the general gas equation P1V1/T1 = P2V2/T2.
- Make V2 the subject: V2 = (P1 V1 T2) / (T1 P2).
- Substitute: V2 = (760 x 250 x 360) / (300 x 1140).
- Numerator = 760 x 250 = 190 000; 190 000 x 360 = 68 400 000. Denominator = 300 x 1140 = 342 000.
- V2 = 68 400 000 / 342 000 = 200 cm^3. The pressure rose by half as much again while the temperature rose by only a fifth, so a smaller volume is the sensible result.
Answer: 200 cm^3
The mistake to avoid
Candidates substitute degrees Celsius directly into Charles's law or the general gas equation. Every gas law demands absolute temperature in kelvin, so add 273 first. The second standard error is adding a temperature change to a latent heat stage: while ice is melting at 0 degrees the temperature does not change at all, so that stage uses Q = ml only, with no (theta2 - theta1) term.
In the exam
Break every calorimetry question into labelled stages and write the formula for each stage before substituting, because the examiner awards marks per stage. Keep masses in kilograms when c is given in J/kg/K. In gas law questions you may leave pressure in mmHg and volume in cm^3 as long as the same unit appears on both sides, since only the ratio matters, but temperature must always be kelvin.